Whakaoti i te -10x*(2x)-10x*(x)=3x

$$- 10 x \cdot ( 2 x ) - 10 x \cdot ( x ) = 3 x$$

Whakaoti mō x

$$x=-\frac{1}{10}=-0.1$$

$$x=0$$

Ngā Upane Whakamahi Tauwehe

Whakareatia te x ki te x, ka x^{2}.

$$-10x^{2}\times 2-10xx=3x$$

Whakareatia te x ki te x, ka x^{2}.

$$-10x^{2}\times 2-10x^{2}=3x$$

Whakareatia te -10 ki te 2, ka -20.

$$-20x^{2}-10x^{2}=3x$$

Pahekotia te -20x^{2} me -10x^{2}, ka -30x^{2}.

$$-30x^{2}=3x$$

Tangohia te 3x mai i ngā taha e rua.

$$-30x^{2}-3x=0$$

Tauwehea te x.

$$x\left(-30x-3\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te -30x-3=0.

$$x=0 x=-\frac{1}{10}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te x ki te x, ka x^{2}.

$$-10x^{2}\times 2-10xx=3x$$

Whakareatia te x ki te x, ka x^{2}.

$$-10x^{2}\times 2-10x^{2}=3x$$

Whakareatia te -10 ki te 2, ka -20.

$$-20x^{2}-10x^{2}=3x$$

Pahekotia te -20x^{2} me -10x^{2}, ka -30x^{2}.

$$-30x^{2}=3x$$

Tangohia te 3x mai i ngā taha e rua.

$$-30x^{2}-3x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -30 mō a, -3 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}}}{2\left(-30\right)}$$

Tuhia te pūtakerua o te \left(-3\right)^{2}.

$$x=\frac{-\left(-3\right)±3}{2\left(-30\right)}$$

Ko te tauaro o -3 ko 3.

$$x=\frac{3±3}{2\left(-30\right)}$$

Whakareatia 2 ki te -30.

$$x=\frac{3±3}{-60}$$

Nā, me whakaoti te whārite x=\frac{3±3}{-60} ina he tāpiri te ±. Tāpiri 3 ki te 3.

$$x=\frac{6}{-60}$$

Whakahekea te hautanga \frac{6}{-60} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 6.

$$x=-\frac{1}{10}$$

Nā, me whakaoti te whārite x=\frac{3±3}{-60} ina he tango te ±. Tango 3 mai i 3.

$$x=\frac{0}{-60}$$

Whakawehe 0 ki te -60.

$$x=0$$

Kua oti te whārite te whakatau.

$$x=-\frac{1}{10} x=0$$

Ngā Upane mō te Whakaoti i te Pūrua

Whakareatia te x ki te x, ka x^{2}.

$$-10x^{2}\times 2-10xx=3x$$

Whakareatia te x ki te x, ka x^{2}.

$$-10x^{2}\times 2-10x^{2}=3x$$

Whakareatia te -10 ki te 2, ka -20.

$$-20x^{2}-10x^{2}=3x$$

Pahekotia te -20x^{2} me -10x^{2}, ka -30x^{2}.

$$-30x^{2}=3x$$

Tangohia te 3x mai i ngā taha e rua.

$$-30x^{2}-3x=0$$

Whakawehea ngā taha e rua ki te -30.

$$\frac{-30x^{2}-3x}{-30}=\frac{0}{-30}$$

Mā te whakawehe ki te -30 ka wetekia te whakareanga ki te -30.

$$x^{2}+\left(-\frac{3}{-30}\right)x=\frac{0}{-30}$$

Whakahekea te hautanga \frac{-3}{-30} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x^{2}+\frac{1}{10}x=\frac{0}{-30}$$

Whakawehe 0 ki te -30.

$$x^{2}+\frac{1}{10}x=0$$

Whakawehea te \frac{1}{10}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te \frac{1}{20}. Nā, tāpiria te pūrua o te \frac{1}{20} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}+\frac{1}{10}x+\left(\frac{1}{20}\right)^{2}=\left(\frac{1}{20}\right)^{2}$$

Pūruatia \frac{1}{20} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}+\frac{1}{10}x+\frac{1}{400}=\frac{1}{400}$$

Tauwehea x^{2}+\frac{1}{10}x+\frac{1}{400}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{1}{20}\right)^{2}=\frac{1}{400}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x+\frac{1}{20}\right)^{2}}=\sqrt{\frac{1}{400}}$$

Whakarūnātia.

$$x+\frac{1}{20}=\frac{1}{20} x+\frac{1}{20}=-\frac{1}{20}$$

Me tango \frac{1}{20} mai i ngā taha e rua o te whārite.

$$x=0 x=-\frac{1}{10}$$