Whakaoti i te -1x^2+2=0

$$- 1 x ^ { 2 } + 2 = 0$$

Whakaoti mō x

$$x=\sqrt{2}\approx 1.414213562$$

$$x=-\sqrt{2}\approx -1.414213562$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-x^{2}=-2$$

Whakawehea ngā taha e rua ki te -1.

$$x^{2}=\frac{-2}{-1}$$

Ka taea te hautanga \frac{-2}{-1} te whakamāmā ki te 2 mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x^{2}=2$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{2} x=-\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-x^{2}+2=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -1 mō a, 0 mō b, me 2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 2}}{2\left(-1\right)}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-1\right)\times 2}}{2\left(-1\right)}$$

Whakareatia -4 ki te -1.

$$x=\frac{0±\sqrt{4\times 2}}{2\left(-1\right)}$$

Whakareatia 4 ki te 2.

$$x=\frac{0±\sqrt{8}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te 8.

$$x=\frac{0±2\sqrt{2}}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$x=\frac{0±2\sqrt{2}}{-2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}}{-2} ina he tāpiri te ±.

$$x=-\sqrt{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}}{-2} ina he tango te ±.

$$x=\sqrt{2}$$

Kua oti te whārite te whakatau.

$$x=-\sqrt{2} x=\sqrt{2}$$