Whakaoti i te -01x^2+0.9x

$$- 01 x ^ { 2 } + 0.9 x$$

Aromātai

$$\frac{9x}{10}$$

Ngā Upane Otinga

Whakareatia te 0 ki te 1, ka 0.

$$0x^{2}+0.9x$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$0+0.9x$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$0.9x$$

Kimi Pārōnaki e ai ki x

$$0.9$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Whakareatia te 0 ki te 1, ka 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0x^{2}+0.9x)$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0+0.9x)$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0.9x)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$0.9x^{1-1}$$

Tango 1 mai i 1.

$$0.9x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$0.9\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$0.9$$