Whakaoti i te -(4)divsqrt{(4)^2-4}*(2)

$$- ( 4 ) \div \sqrt { ( 4 ) ^ { 2 } - 4 } \cdot ( 2 )$$

Aromātai

$$-\frac{4\sqrt{3}}{3}\approx -2.309401077$$

Ngā Upane Otinga

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$\frac{-4}{\sqrt{16-4}}\times 2$$

Tangohia te 4 i te 16, ka 12.

$$\frac{-4}{\sqrt{12}}\times 2$$

Tauwehea te 12=2^{2}\times 3. Tuhia anō te pūtake rua o te hua \sqrt{2^{2}\times 3} hei hua o ngā pūtake rua \sqrt{2^{2}}\sqrt{3}. Tuhia te pūtakerua o te 2^{2}.

$$\frac{-4}{2\sqrt{3}}\times 2$$

Whakangāwaritia te tauraro o \frac{-4}{2\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.

$$\frac{-4\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}\times 2$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{-4\sqrt{3}}{2\times 3}\times 2$$

Me whakakore tahi te 2 i te taurunga me te tauraro.

$$\frac{-2\sqrt{3}}{3}\times 2$$

Tuhia te \frac{-2\sqrt{3}}{3}\times 2 hei hautanga kotahi.

$$\frac{-2\sqrt{3}\times 2}{3}$$

Whakareatia te -2 ki te 2, ka -4.

$$\frac{-4\sqrt{3}}{3}$$