Whakaoti i te -(3x-4)-10(x/5+1)=

$$- ( 3 x - 4 ) - 10 ( \frac { x } { 5 } + 1 ) =$$

Aromātai

$$-5x-6$$

Ngā Upane Otinga

Hei kimi i te tauaro o 3x-4, kimihia te tauaro o ia taurangi.

$$-3x-\left(-4\right)-10\left(\frac{x}{5}+1\right)$$

Ko te tauaro o -4 ko 4.

$$-3x+4-10\left(\frac{x}{5}+1\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 1 ki te \frac{5}{5}.

$$-3x+4-10\left(\frac{x}{5}+\frac{5}{5}\right)$$

Tā te mea he rite te tauraro o \frac{x}{5} me \frac{5}{5}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-3x+4-10\times \frac{x+5}{5}$$

Whakakorea atu te tauwehe pūnoa nui rawa 5 i roto i te 10 me te 5.

$$-3x+4-2\left(x+5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x+5.

$$-3x+4-2x-10$$

Pahekotia te -3x me -2x, ka -5x.

$$-5x+4-10$$

Tangohia te 10 i te 4, ka -6.

$$-5x-6$$

Whakaroha

$$-5x-6$$

Ngā Upane Otinga

Hei kimi i te tauaro o 3x-4, kimihia te tauaro o ia taurangi.

$$-3x-\left(-4\right)-10\left(\frac{x}{5}+1\right)$$

Ko te tauaro o -4 ko 4.

$$-3x+4-10\left(\frac{x}{5}+1\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 1 ki te \frac{5}{5}.

$$-3x+4-10\left(\frac{x}{5}+\frac{5}{5}\right)$$

Tā te mea he rite te tauraro o \frac{x}{5} me \frac{5}{5}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-3x+4-10\times \frac{x+5}{5}$$

Whakakorea atu te tauwehe pūnoa nui rawa 5 i roto i te 10 me te 5.

$$-3x+4-2\left(x+5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x+5.

$$-3x+4-2x-10$$

Pahekotia te -3x me -2x, ka -5x.

$$-5x+4-10$$

Tangohia te 10 i te 4, ka -6.

$$-5x-6$$