Whakaoti i te -(2y+3)-(4y-1)=-12-(3y+2)

$$- ( 2 y + 3 ) - ( 4 y - 1 ) = - 12 - ( 3 y + 2 )$$

Whakaoti mō y

$$y=4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 2y+3, kimihia te tauaro o ia taurangi.

$$-2y-3-\left(4y-1\right)=-12-\left(3y+2\right)$$

Hei kimi i te tauaro o 4y-1, kimihia te tauaro o ia taurangi.

$$-2y-3-4y-\left(-1\right)=-12-\left(3y+2\right)$$

Ko te tauaro o -1 ko 1.

$$-2y-3-4y+1=-12-\left(3y+2\right)$$

Pahekotia te -2y me -4y, ka -6y.

$$-6y-3+1=-12-\left(3y+2\right)$$

Tāpirihia te -3 ki te 1, ka -2.

$$-6y-2=-12-\left(3y+2\right)$$

Hei kimi i te tauaro o 3y+2, kimihia te tauaro o ia taurangi.

$$-6y-2=-12-3y-2$$

Tangohia te 2 i te -12, ka -14.

$$-6y-2=-14-3y$$

Me tāpiri te 3y ki ngā taha e rua.

$$-6y-2+3y=-14$$

Pahekotia te -6y me 3y, ka -3y.

$$-3y-2=-14$$

Me tāpiri te 2 ki ngā taha e rua.

$$-3y=-14+2$$

Tāpirihia te -14 ki te 2, ka -12.

$$-3y=-12$$

Whakawehea ngā taha e rua ki te -3.

$$y=\frac{-12}{-3}$$

Whakawehea te -12 ki te -3, kia riro ko 4.

$$y=4$$