Whakaoti i te -(2+2x^2)+(1/5x+5/4x^2+4/3)-(-2/3-frac{3}{4}x^2+frac{1}{5}x)

$$- ( 2 + 2 x ^ { 2 } ) + ( \frac { 1 } { 5 } x + \frac { 5 } { 4 } x ^ { 2 } + \frac { 4 } { 3 } ) - ( - \frac { 2 } { 3 } - \frac { 3 } { 4 } x ^ { 2 } + \frac { 1 } { 5 } x )$$

Aromātai

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Ngā Upane Otinga

Hei kimi i te tauaro o 2+2x^{2}, kimihia te tauaro o ia taurangi.

$$-2-2x^{2}+\frac{1}{5}x+\frac{5}{4}x^{2}+\frac{4}{3}-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

Pahekotia te -2x^{2} me \frac{5}{4}x^{2}, ka -\frac{3}{4}x^{2}.

$$-2-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{4}{3}-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

Tāpirihia te -2 ki te \frac{4}{3}, ka -\frac{2}{3}.

$$-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

Hei kimi i te tauaro o -\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x, kimihia te tauaro o ia taurangi.

$$-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{2}{3}+\frac{3}{4}x^{2}-\frac{1}{5}x$$

Tāpirihia te -\frac{2}{3} ki te \frac{2}{3}, ka 0.

$$-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{3}{4}x^{2}-\frac{1}{5}x$$

Pahekotia te -\frac{3}{4}x^{2} me \frac{3}{4}x^{2}, ka 0.

$$\frac{1}{5}x-\frac{1}{5}x$$

Pahekotia te \frac{1}{5}x me -\frac{1}{5}x, ka 0.

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Tauwehe

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Ngā Upane Otinga

Tauwehea te \frac{1}{60}.

$$\frac{-120\left(1+x^{2}\right)+12x+75x^{2}+80-\left(-40-45x^{2}+12x\right)}{60}$$

Whakarūnātia.

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