Whakaoti i te -(1-p)=-(2p-2)

$$- ( 1 - p ) = - ( 2 p - 2 )$$

Whakaoti mō p

$$p=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 1-p, kimihia te tauaro o ia taurangi.

$$-1-\left(-p\right)=-\left(2p-2\right)$$

Ko te tauaro o -p ko p.

$$-1+p=-\left(2p-2\right)$$

Hei kimi i te tauaro o 2p-2, kimihia te tauaro o ia taurangi.

$$-1+p=-2p-\left(-2\right)$$

Ko te tauaro o -2 ko 2.

$$-1+p=-2p+2$$

Me tāpiri te 2p ki ngā taha e rua.

$$-1+p+2p=2$$

Pahekotia te p me 2p, ka 3p.

$$-1+3p=2$$

Me tāpiri te 1 ki ngā taha e rua.

$$3p=2+1$$

Tāpirihia te 2 ki te 1, ka 3.

$$3p=3$$

Whakawehea ngā taha e rua ki te 3.

$$p=\frac{3}{3}$$

Whakawehea te 3 ki te 3, kia riro ko 1.

$$p=1$$