Whakaoti i te -sqrt{11}-10x+4=x

$$- \sqrt { 11 } - 10 x + 4 = x$$

Whakaoti mō x

$$x=\frac{4-\sqrt{11}}{11}\approx 0.062125019$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x mai i ngā taha e rua.

$$-\sqrt{11}-10x+4-x=0$$

Pahekotia te -10x me -x, ka -11x.

$$-\sqrt{11}-11x+4=0$$

Me tāpiri te \sqrt{11} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$-11x+4=\sqrt{11}$$

Tangohia te 4 mai i ngā taha e rua.

$$-11x=\sqrt{11}-4$$

Whakawehea ngā taha e rua ki te -11.

$$\frac{-11x}{-11}=\frac{\sqrt{11}-4}{-11}$$

Mā te whakawehe ki te -11 ka wetekia te whakareanga ki te -11.

$$x=\frac{\sqrt{11}-4}{-11}$$

Whakawehe \sqrt{11}-4 ki te -11.

$$x=\frac{4-\sqrt{11}}{11}$$