Whakaoti i te -x^3/8-x^2/4-x/2=

$$- \frac { x ^ { 3 } } { 8 } - \frac { x ^ { 2 } } { 4 } - \frac { x } { 2 } =$$

Aromātai

$$-\frac{x\left(x^{2}+2x+4\right)}{8}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 8 me 4 ko 8. Whakareatia \frac{x^{2}}{4} ki te \frac{2}{2}.

$$-\frac{x^{3}}{8}-\frac{2x^{2}}{8}-\frac{x}{2}$$

Tā te mea he rite te tauraro o -\frac{x^{3}}{8} me \frac{2x^{2}}{8}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{-x^{3}-2x^{2}}{8}-\frac{x}{2}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 8 me 2 ko 8. Whakareatia \frac{x}{2} ki te \frac{4}{4}.

$$\frac{-x^{3}-2x^{2}}{8}-\frac{4x}{8}$$

Tā te mea he rite te tauraro o \frac{-x^{3}-2x^{2}}{8} me \frac{4x}{8}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{-x^{3}-2x^{2}-4x}{8}$$

Tauwehe

$$-\frac{x\left(x^{2}+2x+4\right)}{8}$$

Ngā Upane Otinga

Tauwehea te \frac{1}{8}.

$$\frac{-x^{3}-2x^{2}-4x}{8}$$

Whakaarohia te -x^{3}-2x^{2}-4x. Tauwehea te x.

$$x\left(-x^{2}-2x-4\right)$$

Me tuhi anō te kīanga whakatauwehe katoa. Kāore te pūrau -x^{2}-2x-4 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$\frac{x\left(-x^{2}-2x-4\right)}{8}$$