Whakaoti i te -5/9-2/3v=-2/3

$$- \frac { 5 } { 9 } - \frac { 2 } { 3 } v = - \frac { 2 } { 3 }$$

Whakaoti mō v

$$v=\frac{1}{6}\approx 0.166666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te \frac{5}{9} ki ngā taha e rua.

$$-\frac{2}{3}v=-\frac{2}{3}+\frac{5}{9}$$

Ko te maha noa iti rawa atu o 3 me 9 ko 9. Me tahuri -\frac{2}{3} me \frac{5}{9} ki te hautau me te tautūnga 9.

$$-\frac{2}{3}v=-\frac{6}{9}+\frac{5}{9}$$

Tā te mea he rite te tauraro o -\frac{6}{9} me \frac{5}{9}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-\frac{2}{3}v=\frac{-6+5}{9}$$

Tāpirihia te -6 ki te 5, ka -1.

$$-\frac{2}{3}v=-\frac{1}{9}$$

Me whakarea ngā taha e rua ki te -\frac{3}{2}, te tau utu o -\frac{2}{3}.

$$v=-\frac{1}{9}\left(-\frac{3}{2}\right)$$

Me whakarea te -\frac{1}{9} ki te -\frac{3}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$v=\frac{-\left(-3\right)}{9\times 2}$$

Mahia ngā whakarea i roto i te hautanga \frac{-\left(-3\right)}{9\times 2}.

$$v=\frac{3}{18}$$

Whakahekea te hautanga \frac{3}{18} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$v=\frac{1}{6}$$