Whakaoti i te -4/3sqrt{18}div2sqrt{8}x

$$- \frac { 4 } { 3 } \sqrt { 18 } \div 2 \sqrt { 8 } x$$

Aromātai

$$-8x$$

Ngā Upane Otinga

Tauwehea te 18=3^{2}\times 2. Tuhia anō te pūtake rua o te hua \sqrt{3^{2}\times 2} hei hua o ngā pūtake rua \sqrt{3^{2}}\sqrt{2}. Tuhia te pūtakerua o te 3^{2}.

$$\frac{-\frac{4}{3}\times 3\sqrt{2}}{2}\sqrt{8}x$$

Me whakakore te 3 me te 3.

$$\frac{-4\sqrt{2}}{2}\sqrt{8}x$$

Whakawehea te -4\sqrt{2} ki te 2, kia riro ko -2\sqrt{2}.

$$-2\sqrt{2}\sqrt{8}x$$

Tauwehea te 8=2^{2}\times 2. Tuhia anō te pūtake rua o te hua \sqrt{2^{2}\times 2} hei hua o ngā pūtake rua \sqrt{2^{2}}\sqrt{2}. Tuhia te pūtakerua o te 2^{2}.

$$-2\sqrt{2}\times 2\sqrt{2}x$$

Whakareatia te -2 ki te 2, ka -4.

$$-4\sqrt{2}\sqrt{2}x$$

Whakareatia te \sqrt{2} ki te \sqrt{2}, ka 2.

$$-4\times 2x$$

Whakareatia te -4 ki te 2, ka -8.

$$-8x$$

Kimi Pārōnaki e ai ki x

$$-8$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Tauwehea te 18=3^{2}\times 2. Tuhia anō te pūtake rua o te hua \sqrt{3^{2}\times 2} hei hua o ngā pūtake rua \sqrt{3^{2}}\sqrt{2}. Tuhia te pūtakerua o te 3^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{-\frac{4}{3}\times 3\sqrt{2}}{2}\sqrt{8}x)$$

Me whakakore te 3 me te 3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{-4\sqrt{2}}{2}\sqrt{8}x)$$

Whakawehea te -4\sqrt{2} ki te 2, kia riro ko -2\sqrt{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-2\sqrt{2}\sqrt{8}x)$$

Tauwehea te 8=2^{2}\times 2. Tuhia anō te pūtake rua o te hua \sqrt{2^{2}\times 2} hei hua o ngā pūtake rua \sqrt{2^{2}}\sqrt{2}. Tuhia te pūtakerua o te 2^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-2\sqrt{2}\times 2\sqrt{2}x)$$

Whakareatia te -2 ki te 2, ka -4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-4\sqrt{2}\sqrt{2}x)$$

Whakareatia te \sqrt{2} ki te \sqrt{2}, ka 2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-4\times 2x)$$

Whakareatia te -4 ki te 2, ka -8.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-8x)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$-8x^{1-1}$$

Tango 1 mai i 1.

$$-8x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$-8$$