Whakaoti i te -3/2-4/3y=-2/5

$$- \frac { 3 } { 2 } - \frac { 4 } { 3 } y = - \frac { 2 } { 5 }$$

Whakaoti mō y

$$y=-\frac{33}{40}=-0.825$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te \frac{3}{2} ki ngā taha e rua.

$$-\frac{4}{3}y=-\frac{2}{5}+\frac{3}{2}$$

Ko te maha noa iti rawa atu o 5 me 2 ko 10. Me tahuri -\frac{2}{5} me \frac{3}{2} ki te hautau me te tautūnga 10.

$$-\frac{4}{3}y=-\frac{4}{10}+\frac{15}{10}$$

Tā te mea he rite te tauraro o -\frac{4}{10} me \frac{15}{10}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-\frac{4}{3}y=\frac{-4+15}{10}$$

Tāpirihia te -4 ki te 15, ka 11.

$$-\frac{4}{3}y=\frac{11}{10}$$

Me whakarea ngā taha e rua ki te -\frac{3}{4}, te tau utu o -\frac{4}{3}.

$$y=\frac{11}{10}\left(-\frac{3}{4}\right)$$

Me whakarea te \frac{11}{10} ki te -\frac{3}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$y=\frac{11\left(-3\right)}{10\times 4}$$

Mahia ngā whakarea i roto i te hautanga \frac{11\left(-3\right)}{10\times 4}.

$$y=\frac{-33}{40}$$

Ka taea te hautanga \frac{-33}{40} te tuhi anō ko -\frac{33}{40} mā te tango i te tohu tōraro.

$$y=-\frac{33}{40}$$