Whakaoti i te -2v/R+4piR=0

$$- \frac { 2 v } { R } + 4 \pi R = 0$$

Whakaoti mō v

$$v=2\pi R^{2}$$

$$R\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te R.

$$-2v+4\pi RR=0$$

Whakareatia te R ki te R, ka R^{2}.

$$-2v+4\pi R^{2}=0$$

Tangohia te 4\pi R^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-2v=-4\pi R^{2}$$

Whakawehea ngā taha e rua ki te -2.

$$\frac{-2v}{-2}=-\frac{4\pi R^{2}}{-2}$$

Mā te whakawehe ki te -2 ka wetekia te whakareanga ki te -2.

$$v=-\frac{4\pi R^{2}}{-2}$$

Whakawehe -4\pi R^{2} ki te -2.

$$v=2\pi R^{2}$$

Whakaoti mō R

$$R=\frac{\sqrt{\frac{2v}{\pi }}}{2}$$

$$R=-\frac{\sqrt{\frac{2v}{\pi }}}{2}\text{, }v>0$$