Whakaoti i te -2v/R^2+4piR=0

$$- \frac { 2 v } { R ^ { 2 } } + 4 \pi R = 0$$

Whakaoti mō v

$$v=2\pi R^{3}$$

$$R\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te R^{2}.

$$-2v+4\pi RR^{2}=0$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 1 me te 2 kia riro ai te 3.

$$-2v+4\pi R^{3}=0$$

Tangohia te 4\pi R^{3} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-2v=-4\pi R^{3}$$

Whakawehea ngā taha e rua ki te -2.

$$\frac{-2v}{-2}=-\frac{4\pi R^{3}}{-2}$$

Mā te whakawehe ki te -2 ka wetekia te whakareanga ki te -2.

$$v=-\frac{4\pi R^{3}}{-2}$$

Whakawehe -4\pi R^{3} ki te -2.

$$v=2\pi R^{3}$$

Whakaoti mō R

$$R=\frac{2^{\frac{2}{3}}\sqrt[3]{\frac{v}{\pi }}}{2}$$

$$v\neq 0$$