Whakaoti i te -2(x-3)/9+7/18-x-2/6=x-x-2/3-frac{3(x+1)}{2}

$$- \frac { 2 ( x - 3 ) } { 9 } + \frac { 7 } { 18 } - \frac { x - 2 } { 6 } = x - \frac { x - 2 } { 3 } - \frac { 3 ( x + 1 ) } { 2 }$$

Whakaoti mō x

$$x=-5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 18, arā, te tauraro pātahi he tino iti rawa te kitea o 9,18,6,3,2.

$$-2\times 2\left(x-3\right)+7-3\left(x-2\right)=18x-6\left(x-2\right)-9\times 3\left(x+1\right)$$

Whakareatia te -2 ki te 2, ka -4.

$$-4\left(x-3\right)+7-3\left(x-2\right)=18x-6\left(x-2\right)-9\times 3\left(x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -4 ki te x-3.

$$-4x+12+7-3\left(x-2\right)=18x-6\left(x-2\right)-9\times 3\left(x+1\right)$$

Tāpirihia te 12 ki te 7, ka 19.

$$-4x+19-3\left(x-2\right)=18x-6\left(x-2\right)-9\times 3\left(x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x-2.

$$-4x+19-3x+6=18x-6\left(x-2\right)-9\times 3\left(x+1\right)$$

Pahekotia te -4x me -3x, ka -7x.

$$-7x+19+6=18x-6\left(x-2\right)-9\times 3\left(x+1\right)$$

Tāpirihia te 19 ki te 6, ka 25.

$$-7x+25=18x-6\left(x-2\right)-9\times 3\left(x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -6 ki te x-2.

$$-7x+25=18x-6x+12-9\times 3\left(x+1\right)$$

Pahekotia te 18x me -6x, ka 12x.

$$-7x+25=12x+12-9\times 3\left(x+1\right)$$

Whakareatia te -9 ki te 3, ka -27.

$$-7x+25=12x+12-27\left(x+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -27 ki te x+1.

$$-7x+25=12x+12-27x-27$$

Pahekotia te 12x me -27x, ka -15x.

$$-7x+25=-15x+12-27$$

Tangohia te 27 i te 12, ka -15.

$$-7x+25=-15x-15$$

Me tāpiri te 15x ki ngā taha e rua.

$$-7x+25+15x=-15$$

Pahekotia te -7x me 15x, ka 8x.

$$8x+25=-15$$

Tangohia te 25 mai i ngā taha e rua.

$$8x=-15-25$$

Tangohia te 25 i te -15, ka -40.

$$8x=-40$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{-40}{8}$$

Whakawehea te -40 ki te 8, kia riro ko -5.

$$x=-5$$