Whakaoti i te -2/3x-2leq2/3x

$$- \frac { 2 } { 3 } x - 2 \leq \frac { 2 } { 3 } x$$

Whakaoti mō x

$$x\geq -\frac{3}{2}$$

Ngā Upane Otinga

Tangohia te \frac{2}{3}x mai i ngā taha e rua.

$$-\frac{2}{3}x-2-\frac{2}{3}x\leq 0$$

Pahekotia te -\frac{2}{3}x me -\frac{2}{3}x, ka -\frac{4}{3}x.

$$-\frac{4}{3}x-2\leq 0$$

Me tāpiri te 2 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$-\frac{4}{3}x\leq 2$$

Me whakarea ngā taha e rua ki te -\frac{3}{4}, te tau utu o -\frac{4}{3}. I te mea he tōraro a -\frac{4}{3}, ka huri te ahunga koreōrite.

$$x\geq 2\left(-\frac{3}{4}\right)$$

Tuhia te 2\left(-\frac{3}{4}\right) hei hautanga kotahi.

$$x\geq \frac{2\left(-3\right)}{4}$$

Whakareatia te 2 ki te -3, ka -6.

$$x\geq \frac{-6}{4}$$

Whakahekea te hautanga \frac{-6}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x\geq -\frac{3}{2}$$