Whakaoti i te -1/9(x-27)+1/3(x+3)=x+67

$$- \frac { 1 } { 9 } ( x - 27 ) + \frac { 1 } { 3 } ( x + 3 ) = x + 67$$

Whakaoti mō x

$$x=-81$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{9} ki te x-27.

$$-\frac{1}{9}x-\frac{1}{9}\left(-27\right)+\frac{1}{3}\left(x+3\right)=x+67$$

Tuhia te -\frac{1}{9}\left(-27\right) hei hautanga kotahi.

$$-\frac{1}{9}x+\frac{-\left(-27\right)}{9}+\frac{1}{3}\left(x+3\right)=x+67$$

Whakareatia te -1 ki te -27, ka 27.

$$-\frac{1}{9}x+\frac{27}{9}+\frac{1}{3}\left(x+3\right)=x+67$$

Whakawehea te 27 ki te 9, kia riro ko 3.

$$-\frac{1}{9}x+3+\frac{1}{3}\left(x+3\right)=x+67$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te x+3.

$$-\frac{1}{9}x+3+\frac{1}{3}x+\frac{1}{3}\times 3=x+67$$

Me whakakore te 3 me te 3.

$$-\frac{1}{9}x+3+\frac{1}{3}x+1=x+67$$

Pahekotia te -\frac{1}{9}x me \frac{1}{3}x, ka \frac{2}{9}x.

$$\frac{2}{9}x+3+1=x+67$$

Tāpirihia te 3 ki te 1, ka 4.

$$\frac{2}{9}x+4=x+67$$

Tangohia te x mai i ngā taha e rua.

$$\frac{2}{9}x+4-x=67$$

Pahekotia te \frac{2}{9}x me -x, ka -\frac{7}{9}x.

$$-\frac{7}{9}x+4=67$$

Tangohia te 4 mai i ngā taha e rua.

$$-\frac{7}{9}x=67-4$$

Tangohia te 4 i te 67, ka 63.

$$-\frac{7}{9}x=63$$

Me whakarea ngā taha e rua ki te -\frac{9}{7}, te tau utu o -\frac{7}{9}.

$$x=63\left(-\frac{9}{7}\right)$$

Tuhia te 63\left(-\frac{9}{7}\right) hei hautanga kotahi.

$$x=\frac{63\left(-9\right)}{7}$$

Whakareatia te 63 ki te -9, ka -567.

$$x=\frac{-567}{7}$$

Whakawehea te -567 ki te 7, kia riro ko -81.

$$x=-81$$