Whakaoti i te -1/3(-6-9x)+100x-(x+1)=3(33x+4)-2

$$- \frac { 1 } { 3 } ( - 6 - 9 x ) + 100 x - ( x + 1 ) = 3 ( 33 x + 4 ) - 2$$

Whakaoti mō x

$$x=3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{3} ki te -6-9x.

$$-\frac{1}{3}\left(-6\right)-\frac{1}{3}\left(-9\right)x+100x-\left(x+1\right)=3\left(33x+4\right)-2$$

Tuhia te -\frac{1}{3}\left(-6\right) hei hautanga kotahi.

$$\frac{-\left(-6\right)}{3}-\frac{1}{3}\left(-9\right)x+100x-\left(x+1\right)=3\left(33x+4\right)-2$$

Whakareatia te -1 ki te -6, ka 6.

$$\frac{6}{3}-\frac{1}{3}\left(-9\right)x+100x-\left(x+1\right)=3\left(33x+4\right)-2$$

Whakawehea te 6 ki te 3, kia riro ko 2.

$$2-\frac{1}{3}\left(-9\right)x+100x-\left(x+1\right)=3\left(33x+4\right)-2$$

Tuhia te -\frac{1}{3}\left(-9\right) hei hautanga kotahi.

$$2+\frac{-\left(-9\right)}{3}x+100x-\left(x+1\right)=3\left(33x+4\right)-2$$

Whakareatia te -1 ki te -9, ka 9.

$$2+\frac{9}{3}x+100x-\left(x+1\right)=3\left(33x+4\right)-2$$

Whakawehea te 9 ki te 3, kia riro ko 3.

$$2+3x+100x-\left(x+1\right)=3\left(33x+4\right)-2$$

Pahekotia te 3x me 100x, ka 103x.

$$2+103x-\left(x+1\right)=3\left(33x+4\right)-2$$

Hei kimi i te tauaro o x+1, kimihia te tauaro o ia taurangi.

$$2+103x-x-1=3\left(33x+4\right)-2$$

Pahekotia te 103x me -x, ka 102x.

$$2+102x-1=3\left(33x+4\right)-2$$

Tangohia te 1 i te 2, ka 1.

$$1+102x=3\left(33x+4\right)-2$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 33x+4.

$$1+102x=99x+12-2$$

Tangohia te 2 i te 12, ka 10.

$$1+102x=99x+10$$

Tangohia te 99x mai i ngā taha e rua.

$$1+102x-99x=10$$

Pahekotia te 102x me -99x, ka 3x.

$$1+3x=10$$

Tangohia te 1 mai i ngā taha e rua.

$$3x=10-1$$

Tangohia te 1 i te 10, ka 9.

$$3x=9$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{9}{3}$$

Whakawehea te 9 ki te 3, kia riro ko 3.

$$x=3$$