Whakaoti i te -1/2(x-5)^2+6=y

$$- \frac { 1 } { 2 } ( x - 5 ) ^ { 2 } + 6 = y$$

Whakaoti mō y

$$y=-\frac{\left(x-5\right)^{2}}{2}+6$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-5\right)^{2}.

$$-\frac{1}{2}\left(x^{2}-10x+25\right)+6=y$$

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{2} ki te x^{2}-10x+25.

$$-\frac{1}{2}x^{2}+5x-\frac{25}{2}+6=y$$

Tāpirihia te -\frac{25}{2} ki te 6, ka -\frac{13}{2}.

$$-\frac{1}{2}x^{2}+5x-\frac{13}{2}=y$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$y=-\frac{1}{2}x^{2}+5x-\frac{13}{2}$$

Whakaoti mō x (complex solution)

$$x=-\sqrt{12-2y}+5$$

$$x=\sqrt{12-2y}+5$$

Whakaoti mō x

$$x=-\sqrt{12-2y}+5$$

$$x=\sqrt{12-2y}+5\text{, }y\leq 6$$