Whakaoti i te -1/2(2x-10y-3)=-1x+10y

$$- \frac { 1 } { 2 } ( 2 x - 10 y - 3 ) = - 1 x + 10 y$$

Whakaoti mō y

$$y = \frac{3}{10} = 0.3$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{2} ki te 2x-10y-3.

$$-x+5y+\frac{3}{2}=-x+10y$$

Tangohia te 10y mai i ngā taha e rua.

$$-x+5y+\frac{3}{2}-10y=-x$$

Pahekotia te 5y me -10y, ka -5y.

$$-x-5y+\frac{3}{2}=-x$$

Me tāpiri te x ki ngā taha e rua.

$$-5y+\frac{3}{2}=-x+x$$

Pahekotia te -x me x, ka 0.

$$-5y+\frac{3}{2}=0$$

Tangohia te \frac{3}{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-5y=-\frac{3}{2}$$

Whakawehea ngā taha e rua ki te -5.

$$y=\frac{-\frac{3}{2}}{-5}$$

Tuhia te \frac{-\frac{3}{2}}{-5} hei hautanga kotahi.

$$y=\frac{-3}{2\left(-5\right)}$$

Whakareatia te 2 ki te -5, ka -10.

$$y=\frac{-3}{-10}$$

Ka taea te hautanga \frac{-3}{-10} te whakamāmā ki te \frac{3}{10} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$y=\frac{3}{10}$$

Whakaoti mō x (complex solution)

$$x\in \mathrm{C}$$

$$y = \frac{3}{10} = 0.3$$

Whakaoti mō x

$$x\in \mathrm{R}$$

$$y = \frac{3}{10} = 0.3$$