Whakaoti i te (y+2)(y+2)=16x

$$(y+2)(y+2)=16x$$

Whakaoti mō x

$$x=\frac{\left(y+2\right)^{2}}{16}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te y+2 ki te y+2, ka \left(y+2\right)^{2}.

$$\left(y+2\right)^{2}=16x$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(y+2\right)^{2}.

$$y^{2}+4y+4=16x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$16x=y^{2}+4y+4$$

Whakawehea ngā taha e rua ki te 16.

$$\frac{16x}{16}=\frac{\left(y+2\right)^{2}}{16}$$

Mā te whakawehe ki te 16 ka wetekia te whakareanga ki te 16.

$$x=\frac{\left(y+2\right)^{2}}{16}$$

Whakaoti mō y (complex solution)

$$y=-4\sqrt{x}-2$$

$$y=4\sqrt{x}-2$$

Whakaoti mō y

$$y=-4\sqrt{x}-2$$

$$y=4\sqrt{x}-2\text{, }x\geq 0$$