Whakaoti i te (x-9+-x^2-25/2x+5)*(2x+5)

$$(x-9+ \frac{ - { x }^{ 2 } -25 }{ 2x+5 } ) \times (2x+5)$$

Aromātai

$$x^{2}-13x-70$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x-9 ki te \frac{2x+5}{2x+5}.

$$\left(\frac{\left(x-9\right)\left(2x+5\right)}{2x+5}+\frac{-x^{2}-25}{2x+5}\right)\left(2x+5\right)$$

Tā te mea he rite te tauraro o \frac{\left(x-9\right)\left(2x+5\right)}{2x+5} me \frac{-x^{2}-25}{2x+5}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\left(x-9\right)\left(2x+5\right)-x^{2}-25}{2x+5}\left(2x+5\right)$$

Mahia ngā whakarea i roto o \left(x-9\right)\left(2x+5\right)-x^{2}-25.

$$\frac{2x^{2}+5x-18x-45-x^{2}-25}{2x+5}\left(2x+5\right)$$

Whakakotahitia ngā kupu rite i 2x^{2}+5x-18x-45-x^{2}-25.

$$\frac{x^{2}-13x-70}{2x+5}\left(2x+5\right)$$

Me whakakore te 2x+5 me te 2x+5.

$$x^{2}-13x-70$$

Whakaroha

$$x^{2}-13x-70$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x-9 ki te \frac{2x+5}{2x+5}.

$$\left(\frac{\left(x-9\right)\left(2x+5\right)}{2x+5}+\frac{-x^{2}-25}{2x+5}\right)\left(2x+5\right)$$

Tā te mea he rite te tauraro o \frac{\left(x-9\right)\left(2x+5\right)}{2x+5} me \frac{-x^{2}-25}{2x+5}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\left(x-9\right)\left(2x+5\right)-x^{2}-25}{2x+5}\left(2x+5\right)$$

Mahia ngā whakarea i roto o \left(x-9\right)\left(2x+5\right)-x^{2}-25.

$$\frac{2x^{2}+5x-18x-45-x^{2}-25}{2x+5}\left(2x+5\right)$$

Whakakotahitia ngā kupu rite i 2x^{2}+5x-18x-45-x^{2}-25.

$$\frac{x^{2}-13x-70}{2x+5}\left(2x+5\right)$$

Me whakakore te 2x+5 me te 2x+5.

$$x^{2}-13x-70$$