Whakaoti i te (x-1)x^2+(x+4)y+x+7=0

$$(x-1) { x }^{ 2 } +(x+4)y+x+7=0$$

Whakaoti mō y

$$y=-\frac{x^{3}-x^{2}+x+7}{x+4}$$

$$x\neq -4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te x-1 ki te x^{2}.

$$x^{3}-x^{2}+\left(x+4\right)y+x+7=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+4 ki te y.

$$x^{3}-x^{2}+xy+4y+x+7=0$$

Tangohia te x^{3} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-x^{2}+xy+4y+x+7=-x^{3}$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$xy+4y+x+7=-x^{3}+x^{2}$$

Tangohia te x mai i ngā taha e rua.

$$xy+4y+7=-x^{3}+x^{2}-x$$

Tangohia te 7 mai i ngā taha e rua.

$$xy+4y=-x^{3}+x^{2}-x-7$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(x+4\right)y=-x^{3}+x^{2}-x-7$$

Whakawehea ngā taha e rua ki te x+4.

$$\frac{\left(x+4\right)y}{x+4}=\frac{-x^{3}+x^{2}-x-7}{x+4}$$

Mā te whakawehe ki te x+4 ka wetekia te whakareanga ki te x+4.

$$y=\frac{-x^{3}+x^{2}-x-7}{x+4}$$