Whakaoti i te (x+3)(x-3)=3(-1)

$$(x+3)(x-3)=3(-1)$$

Whakaoti mō x

$$x=\sqrt{6}\approx 2.449489743$$

$$x=-\sqrt{6}\approx -2.449489743$$

Ngā Upane mā te Kimi Pūtakerua

Whakaarohia te \left(x+3\right)\left(x-3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$x^{2}-9=3\left(-1\right)$$

Whakareatia te 3 ki te -1, ka -3.

$$x^{2}-9=-3$$

Me tāpiri te 9 ki ngā taha e rua.

$$x^{2}=-3+9$$

Tāpirihia te -3 ki te 9, ka 6.

$$x^{2}=6$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{6} x=-\sqrt{6}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakaarohia te \left(x+3\right)\left(x-3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$x^{2}-9=3\left(-1\right)$$

Whakareatia te 3 ki te -1, ka -3.

$$x^{2}-9=-3$$

Me tāpiri te 3 ki ngā taha e rua.

$$x^{2}-9+3=0$$

Tāpirihia te -9 ki te 3, ka -6.

$$x^{2}-6=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -6 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-6\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-6\right)}}{2}$$

Whakareatia -4 ki te -6.

$$x=\frac{0±\sqrt{24}}{2}$$

Tuhia te pūtakerua o te 24.

$$x=\frac{0±2\sqrt{6}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{6}}{2} ina he tāpiri te ±.

$$x=\sqrt{6}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{6}}{2} ina he tango te ±.

$$x=-\sqrt{6}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{6} x=-\sqrt{6}$$