Whakaoti i te (x+10)(x+10)=100

$$(x+10)(x+10)=100$$

Whakaoti mō x

$$x=0$$

$$x=-20$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te x+10 ki te x+10, ka \left(x+10\right)^{2}.

$$\left(x+10\right)^{2}=100$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+10\right)^{2}.

$$x^{2}+20x+100=100$$

Tangohia te 100 mai i ngā taha e rua.

$$x^{2}+20x+100-100=0$$

Tangohia te 100 i te 100, ka 0.

$$x^{2}+20x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 20 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-20±\sqrt{20^{2}}}{2}$$

Tuhia te pūtakerua o te 20^{2}.

$$x=\frac{-20±20}{2}$$

Nā, me whakaoti te whārite x=\frac{-20±20}{2} ina he tāpiri te ±. Tāpiri -20 ki te 20.

$$x=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$x=0$$

Nā, me whakaoti te whārite x=\frac{-20±20}{2} ina he tango te ±. Tango 20 mai i -20.

$$x=-\frac{40}{2}$$

Whakawehe -40 ki te 2.

$$x=-20$$

Kua oti te whārite te whakatau.

$$x=0 x=-20$$

Ngā Upane mō te Whakaoti i te Pūrua

Whakareatia te x+10 ki te x+10, ka \left(x+10\right)^{2}.

$$\left(x+10\right)^{2}=100$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x+10\right)^{2}}=\sqrt{100}$$

Whakarūnātia.

$$x+10=10 x+10=-10$$

Me tango 10 mai i ngā taha e rua o te whārite.

$$x=0 x=-20$$