Whakaoti i te (45*32){left(8/3right)}^2x=23

$$(45 \times 32) { \left( \frac{ 8 }{ 3 } \right) }^{ 2x } =23$$

Whakaoti mō x

$$x=\frac{\log_{\frac{8}{3}}\left(\frac{23}{1440}\right)}{2}\approx -2.108880911$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$1440\times \left(\frac{8}{3}\right)^{2x}=23$$

Whakawehea ngā taha e rua ki te 1440.

$$\left(\frac{8}{3}\right)^{2x}=\frac{23}{1440}$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(\left(\frac{8}{3}\right)^{2x})=\log(\frac{23}{1440})$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$2x\log(\frac{8}{3})=\log(\frac{23}{1440})$$

Whakawehea ngā taha e rua ki te \log(\frac{8}{3}).

$$2x=\frac{\log(\frac{23}{1440})}{\log(\frac{8}{3})}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$2x=\log_{\frac{8}{3}}\left(\frac{23}{1440}\right)$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{\ln(\frac{23}{1440})}{2\ln(\frac{8}{3})}$$

Whakaoti mō x (complex solution)

$$x=\frac{\pi n_{1}i}{\ln(\frac{8}{3})}+\frac{\log_{\frac{8}{3}}\left(\frac{23}{1440}\right)}{2}$$

$$n_{1}\in \mathrm{Z}$$