Whakaoti i te (3x-2)(2x-3)=(6x+5)(x+1)-1

$$(3x-2)(2x-3)=(6x+5)(x+1)-1$$

Whakaoti mō x

$$x=\frac{1}{12}\approx 0.083333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te 3x-2 ki te 2x-3 ka whakakotahi i ngā kupu rite.

$$6x^{2}-13x+6=\left(6x+5\right)\left(x+1\right)-1$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 6x+5 ki te x+1 ka whakakotahi i ngā kupu rite.

$$6x^{2}-13x+6=6x^{2}+11x+5-1$$

Tangohia te 1 i te 5, ka 4.

$$6x^{2}-13x+6=6x^{2}+11x+4$$

Tangohia te 6x^{2} mai i ngā taha e rua.

$$6x^{2}-13x+6-6x^{2}=11x+4$$

Pahekotia te 6x^{2} me -6x^{2}, ka 0.

$$-13x+6=11x+4$$

Tangohia te 11x mai i ngā taha e rua.

$$-13x+6-11x=4$$

Pahekotia te -13x me -11x, ka -24x.

$$-24x+6=4$$

Tangohia te 6 mai i ngā taha e rua.

$$-24x=4-6$$

Tangohia te 6 i te 4, ka -2.

$$-24x=-2$$

Whakawehea ngā taha e rua ki te -24.

$$x=\frac{-2}{-24}$$

Whakahekea te hautanga \frac{-2}{-24} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x=\frac{1}{12}$$