Whakaoti i te (3x-2)(2x+5)=(6x-1)(x+4

$$(3x-2)(2x+5)=(6x-1)(x+4$$

Whakaoti mō x

$$x=-\frac{1}{2}=-0.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te 3x-2 ki te 2x+5 ka whakakotahi i ngā kupu rite.

$$6x^{2}+11x-10=\left(6x-1\right)\left(x+4\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 6x-1 ki te x+4 ka whakakotahi i ngā kupu rite.

$$6x^{2}+11x-10=6x^{2}+23x-4$$

Tangohia te 6x^{2} mai i ngā taha e rua.

$$6x^{2}+11x-10-6x^{2}=23x-4$$

Pahekotia te 6x^{2} me -6x^{2}, ka 0.

$$11x-10=23x-4$$

Tangohia te 23x mai i ngā taha e rua.

$$11x-10-23x=-4$$

Pahekotia te 11x me -23x, ka -12x.

$$-12x-10=-4$$

Me tāpiri te 10 ki ngā taha e rua.

$$-12x=-4+10$$

Tāpirihia te -4 ki te 10, ka 6.

$$-12x=6$$

Whakawehea ngā taha e rua ki te -12.

$$x=\frac{6}{-12}$$

Whakahekea te hautanga \frac{6}{-12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 6.

$$x=-\frac{1}{2}$$