Whakaoti i te (3+2sqrt{2})(3-2sqrt{2})(3+2sqrt{2}-3+2sqrt{2}=

$$(3+2 \sqrt{ 2 } )(3-2 \sqrt{ 2 } )(3+2 \sqrt{ 2 } -3+2 \sqrt{ 2 } =$$

Aromātai

$$4\sqrt{2}\approx 5.656854249$$

Ngā Upane Otinga

Tangohia te 3 i te 3, ka 0.

$$\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)\left(2\sqrt{2}+2\sqrt{2}\right)$$

Pahekotia te 2\sqrt{2} me 2\sqrt{2}, ka 4\sqrt{2}.

$$\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)\times 4\sqrt{2}$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 3+2\sqrt{2} ki ia tau o 3-2\sqrt{2}.

$$\left(9-6\sqrt{2}+6\sqrt{2}-4\left(\sqrt{2}\right)^{2}\right)\times 4\sqrt{2}$$

Pahekotia te -6\sqrt{2} me 6\sqrt{2}, ka 0.

$$\left(9-4\left(\sqrt{2}\right)^{2}\right)\times 4\sqrt{2}$$

Ko te pūrua o \sqrt{2} ko 2.

$$\left(9-4\times 2\right)\times 4\sqrt{2}$$

Whakareatia te -4 ki te 2, ka -8.

$$\left(9-8\right)\times 4\sqrt{2}$$

Tangohia te 8 i te 9, ka 1.

$$1\times 4\sqrt{2}$$

Whakareatia te 1 ki te 4, ka 4.

$$4\sqrt{2}$$