Whakaoti i te (2(x+10)+3)div3*25=4x+05

$$(2(x+10)+3) \div 3 \times 25=4x+05$$

Whakaoti mō x

$$x = -\frac{575}{38} = -15\frac{5}{38} \approx -15.131578947$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 3.

$$\left(2\left(x+10\right)+3\right)\times 25=12x+0\times 5$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x+10.

$$\left(2x+20+3\right)\times 25=12x+0\times 5$$

Tāpirihia te 20 ki te 3, ka 23.

$$\left(2x+23\right)\times 25=12x+0\times 5$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2x+23 ki te 25.

$$50x+575=12x+0\times 5$$

Whakareatia te 0 ki te 5, ka 0.

$$50x+575=12x+0$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$50x+575=12x$$

Tangohia te 12x mai i ngā taha e rua.

$$50x+575-12x=0$$

Pahekotia te 50x me -12x, ka 38x.

$$38x+575=0$$

Tangohia te 575 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$38x=-575$$

Whakawehea ngā taha e rua ki te 38.

$$x=\frac{-575}{38}$$

Ka taea te hautanga \frac{-575}{38} te tuhi anō ko -\frac{575}{38} mā te tango i te tohu tōraro.

$$x=-\frac{575}{38}$$