Whakaoti i te (2x^3+2x^2-3x+2)+(x^3-3x^2+4x-4)

$$(2 { x }^{ 3 } +2 { x }^{ 2 } -3x+2)+( { x }^{ 3 } -3 { x }^{ 2 } +4x-4)$$

Aromātai

$$3x^{3}-x^{2}+x-2$$

Ngā Upane Otinga

Pahekotia te 2x^{3} me x^{3}, ka 3x^{3}.

$$3x^{3}+2x^{2}-3x+2-3x^{2}+4x-4$$

Pahekotia te 2x^{2} me -3x^{2}, ka -x^{2}.

$$3x^{3}-x^{2}-3x+2+4x-4$$

Pahekotia te -3x me 4x, ka x.

$$3x^{3}-x^{2}+x+2-4$$

Tangohia te 4 i te 2, ka -2.

$$3x^{3}-x^{2}+x-2$$

Kimi Pārōnaki e ai ki x

$$9x^{2}-2x+1$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 2x^{3} me x^{3}, ka 3x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{3}+2x^{2}-3x+2-3x^{2}+4x-4)$$

Pahekotia te 2x^{2} me -3x^{2}, ka -x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{3}-x^{2}-3x+2+4x-4)$$

Pahekotia te -3x me 4x, ka x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{3}-x^{2}+x+2-4)$$

Tangohia te 4 i te 2, ka -2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{3}-x^{2}+x-2)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 3x^{3-1}+2\left(-1\right)x^{2-1}+x^{1-1}$$

Whakareatia 3 ki te 3.

$$9x^{3-1}+2\left(-1\right)x^{2-1}+x^{1-1}$$

Tango 1 mai i 3.

$$9x^{2}+2\left(-1\right)x^{2-1}+x^{1-1}$$

Whakareatia 2 ki te -1.

$$9x^{2}-2x^{2-1}+x^{1-1}$$

Tango 1 mai i 2.

$$9x^{2}-2x^{1}+x^{1-1}$$

Tango 1 mai i 1.

$$9x^{2}-2x^{1}+x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$9x^{2}-2x+x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$9x^{2}-2x+1$$