Whakaoti i te (12x^2)*(1/x-2)

$$(12 { x }^{ 2 } ) \times ( \frac{ 1 }{ x-2 } )$$

Aromātai

$$\frac{12x^{2}}{x-2}$$

Ngā Upane Otinga

Tuhia te 12\times \frac{1}{x-2} hei hautanga kotahi.

$$\frac{12}{x-2}x^{2}$$

Tuhia te \frac{12}{x-2}x^{2} hei hautanga kotahi.

$$\frac{12x^{2}}{x-2}$$

Kimi Pārōnaki e ai ki x

$$\frac{12x\left(x-4\right)}{\left(x-2\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Tuhia te 12\times \frac{1}{x-2} hei hautanga kotahi.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{12}{x-2}x^{2})$$

Tuhia te \frac{12}{x-2}x^{2} hei hautanga kotahi.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{12x^{2}}{x-2})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}-2\right)\frac{\mathrm{d}}{\mathrm{d}x}(12x^{2})-12x^{2}\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}-2)}{\left(x^{1}-2\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}-2\right)\times 2\times 12x^{2-1}-12x^{2}x^{1-1}}{\left(x^{1}-2\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}-2\right)\times 24x^{1}-12x^{2}x^{0}}{\left(x^{1}-2\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}\times 24x^{1}-2\times 24x^{1}-12x^{2}x^{0}}{\left(x^{1}-2\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{24x^{1+1}-2\times 24x^{1}-12x^{2}}{\left(x^{1}-2\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{24x^{2}-48x^{1}-12x^{2}}{\left(x^{1}-2\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(24-12\right)x^{2}-48x^{1}}{\left(x^{1}-2\right)^{2}}$$

Tango 12 mai i 24.

$$\frac{12x^{2}-48x^{1}}{\left(x^{1}-2\right)^{2}}$$

Tauwehea te 12x.

$$\frac{12x\left(x^{1}-4x^{0}\right)}{\left(x^{1}-2\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{12x\left(x-4x^{0}\right)}{\left(x-2\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{12x\left(x-4\right)}{\left(x-2\right)^{2}}$$