Whakaoti i te (100-x)y(1+0.02x)=100x

$$(100-x)y(1+0.02x)=100x$$

Whakaoti mō y

$$y=-\frac{5000x}{\left(x-100\right)\left(x+50\right)}$$

$$x\neq -50\text{ and }x\neq 100$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 100-x ki te y.

$$\left(100y-xy\right)\left(1+0.02x\right)=100x$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 100y-xy ki te 1+0.02x ka whakakotahi i ngā kupu rite.

$$100y+yx-0.02x^{2}y=100x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(100+x-0.02x^{2}\right)y=100x$$

He hanga arowhānui tō te whārite.

$$\left(-\frac{x^{2}}{50}+x+100\right)y=100x$$

Whakawehea ngā taha e rua ki te 100+x-0.02x^{2}.

$$\frac{\left(-\frac{x^{2}}{50}+x+100\right)y}{-\frac{x^{2}}{50}+x+100}=\frac{100x}{-\frac{x^{2}}{50}+x+100}$$

Mā te whakawehe ki te 100+x-0.02x^{2} ka wetekia te whakareanga ki te 100+x-0.02x^{2}.

$$y=\frac{100x}{-\frac{x^{2}}{50}+x+100}$$

Whakawehe 100x ki te 100+x-0.02x^{2}.

$$y=-\frac{5000x}{\left(x-100\right)\left(x+50\right)}$$

Whakaoti mō x

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x=-\frac{25\left(\sqrt{9y^{2}-200y+10000}-y+100\right)}{y}\text{; }x=-\frac{25\left(-\sqrt{9y^{2}-200y+10000}-y+100\right)}{y}\text{, }&y\neq 0\end{matrix}\right.$$