Whakaoti i te (-4+2/3)=x9+5

$$(-4+ \frac{ 2 }{ 3 } )=x9+5$$

Whakaoti mō x_9

$$x_{9} = -\frac{25}{3} = -8\frac{1}{3} \approx -8.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tahuri te -4 ki te hautau -\frac{12}{3}.

$$-\frac{12}{3}+\frac{2}{3}=x_{9}+5$$

Tā te mea he rite te tauraro o -\frac{12}{3} me \frac{2}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{-12+2}{3}=x_{9}+5$$

Tāpirihia te -12 ki te 2, ka -10.

$$-\frac{10}{3}=x_{9}+5$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x_{9}+5=-\frac{10}{3}$$

Tangohia te 5 mai i ngā taha e rua.

$$x_{9}=-\frac{10}{3}-5$$

Me tahuri te 5 ki te hautau \frac{15}{3}.

$$x_{9}=-\frac{10}{3}-\frac{15}{3}$$

Tā te mea he rite te tauraro o -\frac{10}{3} me \frac{15}{3}, me tango rāua mā te tango i ō raua taurunga.

$$x_{9}=\frac{-10-15}{3}$$

Tangohia te 15 i te -10, ka -25.

$$x_{9}=-\frac{25}{3}$$