Whakaoti i te (-3)div(-sqrt{5}-2)=

$$(-3) \div (- \sqrt{ 5 } -2)=$$

Aromātai

$$3\left(\sqrt{5}-2\right)\approx 0.708203932$$

Ngā Upane Otinga

Whakangāwaritia te tauraro o \frac{-3}{-\sqrt{5}-2} mā te whakarea i te taurunga me te tauraro ki te -\sqrt{5}+2.

$$\frac{-3\left(-\sqrt{5}+2\right)}{\left(-\sqrt{5}-2\right)\left(-\sqrt{5}+2\right)}$$

Whakaarohia te \left(-\sqrt{5}-2\right)\left(-\sqrt{5}+2\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{-3\left(-\sqrt{5}+2\right)}{\left(-\sqrt{5}\right)^{2}-2^{2}}$$

Tātaihia te -\sqrt{5} mā te pū o 2, kia riro ko \left(\sqrt{5}\right)^{2}.

$$\frac{-3\left(-\sqrt{5}+2\right)}{\left(\sqrt{5}\right)^{2}-2^{2}}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$\frac{-3\left(-\sqrt{5}+2\right)}{\left(\sqrt{5}\right)^{2}-4}$$

Ko te pūrua o \sqrt{5} ko 5.

$$\frac{-3\left(-\sqrt{5}+2\right)}{5-4}$$

Tangohia te 4 i te 5, ka 1.

$$\frac{-3\left(-\sqrt{5}+2\right)}{1}$$

Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$-3\left(-\sqrt{5}+2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te -\sqrt{5}+2.

$$-3\left(-\sqrt{5}\right)-6$$

Whakareatia te -3 ki te -1, ka 3.

$$3\sqrt{5}-6$$