Whakaoti i te ((-11)+1)div(sqrt{8-11}-3)

$$((-11)+1) \div ( \sqrt{ 8-11 } -3)$$

Aromātai

$$\text{Indeterminate}$$

Ngā Upane Otinga

Tāpirihia te -11 ki te 1, ka -10.

$$\frac{-10}{\sqrt{8-11}-3}$$

Tangohia te 11 i te 8, ka -3.

$$\frac{-10}{\sqrt{-3}-3}$$

Whakangāwaritia te tauraro o \frac{-10}{\sqrt{-3}-3} mā te whakarea i te taurunga me te tauraro ki te \sqrt{-3}+3.

$$\frac{-10\left(\sqrt{-3}+3\right)}{\left(\sqrt{-3}-3\right)\left(\sqrt{-3}+3\right)}$$

Whakaarohia te \left(\sqrt{-3}-3\right)\left(\sqrt{-3}+3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{-10\left(\sqrt{-3}+3\right)}{\left(\sqrt{-3}\right)^{2}-3^{2}}$$

Pūrua \sqrt{-3}. Pūrua 3.

$$\frac{-10\left(\sqrt{-3}+3\right)}{-3-9}$$

Tangohia te 9 i te -3, ka -12.

$$\frac{-10\left(\sqrt{-3}+3\right)}{-12}$$

Whakawehea te -10\left(\sqrt{-3}+3\right) ki te -12, kia riro ko \frac{5}{6}\left(\sqrt{-3}+3\right).

$$\frac{5}{6}\left(\sqrt{-3}+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{5}{6} ki te \sqrt{-3}+3.

$$\frac{5}{6}\sqrt{-3}+\frac{5}{6}\times 3$$

Tuhia te \frac{5}{6}\times 3 hei hautanga kotahi.

$$\frac{5}{6}\sqrt{-3}+\frac{5\times 3}{6}$$

Whakareatia te 5 ki te 3, ka 15.

$$\frac{5}{6}\sqrt{-3}+\frac{15}{6}$$

Whakahekea te hautanga \frac{15}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$\frac{5}{6}\sqrt{-3}+\frac{5}{2}$$