Whakaoti i te (y-6)^2-(y+4)^2=0

$$( y - 6 ) ^ { 2 } - ( y + 4 ) ^ { 2 } = 0$$

Whakaoti mō y

$$y=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(y-6\right)^{2}.

$$y^{2}-12y+36-\left(y+4\right)^{2}=0$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(y+4\right)^{2}.

$$y^{2}-12y+36-\left(y^{2}+8y+16\right)=0$$

Hei kimi i te tauaro o y^{2}+8y+16, kimihia te tauaro o ia taurangi.

$$y^{2}-12y+36-y^{2}-8y-16=0$$

Pahekotia te y^{2} me -y^{2}, ka 0.

$$-12y+36-8y-16=0$$

Pahekotia te -12y me -8y, ka -20y.

$$-20y+36-16=0$$

Tangohia te 16 i te 36, ka 20.

$$-20y+20=0$$

Tangohia te 20 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-20y=-20$$

Whakawehea ngā taha e rua ki te -20.

$$y=\frac{-20}{-20}$$

Whakawehea te -20 ki te -20, kia riro ko 1.

$$y=1$$