Whakaoti i te (y-2)^2=4(x-1)

$$( y - 2 ) ^ { 2 } = 4 ( x - 1 )$$

Whakaoti mō x

$$x=\frac{\left(y-2\right)^{2}+4}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(y-2\right)^{2}.

$$y^{2}-4y+4=4\left(x-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x-1.

$$y^{2}-4y+4=4x-4$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$4x-4=y^{2}-4y+4$$

Me tāpiri te 4 ki ngā taha e rua.

$$4x=y^{2}-4y+4+4$$

Tāpirihia te 4 ki te 4, ka 8.

$$4x=y^{2}-4y+8$$

Whakawehea ngā taha e rua ki te 4.

$$\frac{4x}{4}=\frac{y^{2}-4y+8}{4}$$

Mā te whakawehe ki te 4 ka wetekia te whakareanga ki te 4.

$$x=\frac{y^{2}-4y+8}{4}$$

Whakawehe y^{2}-4y+8 ki te 4.

$$x=\frac{y^{2}}{4}-y+2$$

Whakaoti mō y (complex solution)

$$y=-2\sqrt{x-1}+2$$

$$y=2\sqrt{x-1}+2$$

Whakaoti mō y

$$y=-2\sqrt{x-1}+2$$

$$y=2\sqrt{x-1}+2\text{, }x\geq 1$$