Whakaoti i te (x-5)^2=7

$$( x - 5 ) ^ { 2 } = 7$$

Whakaoti mō x

$$x=\sqrt{7}+5\approx 7.645751311$$

$$x=5-\sqrt{7}\approx 2.354248689$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x-5=\sqrt{7} x-5=-\sqrt{7}$$

Me tāpiri 5 ki ngā taha e rua o te whārite.

$$x-5-\left(-5\right)=\sqrt{7}-\left(-5\right) x-5-\left(-5\right)=-\sqrt{7}-\left(-5\right)$$

Mā te tango i te -5 i a ia ake anō ka toe ko te 0.

$$x=\sqrt{7}-\left(-5\right) x=-\sqrt{7}-\left(-5\right)$$

Tango -5 mai i \sqrt{7}.

$$x=\sqrt{7}+5$$

Tango -5 mai i -\sqrt{7}.

$$x=5-\sqrt{7}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{7}+5 x=5-\sqrt{7}$$