Whakaoti i te (x-3)(x+3)=2*4

$$( x - 3 ) ( x + 3 ) = 2 \times 4$$

Whakaoti mō x

$$x=\sqrt{17}\approx 4.123105626$$

$$x=-\sqrt{17}\approx -4.123105626$$

Ngā Upane mā te Kimi Pūtakerua

Whakaarohia te \left(x-3\right)\left(x+3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$x^{2}-9=2\times 4$$

Whakareatia te 2 ki te 4, ka 8.

$$x^{2}-9=8$$

Me tāpiri te 9 ki ngā taha e rua.

$$x^{2}=8+9$$

Tāpirihia te 8 ki te 9, ka 17.

$$x^{2}=17$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{17} x=-\sqrt{17}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakaarohia te \left(x-3\right)\left(x+3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$x^{2}-9=2\times 4$$

Whakareatia te 2 ki te 4, ka 8.

$$x^{2}-9=8$$

Tangohia te 8 mai i ngā taha e rua.

$$x^{2}-9-8=0$$

Tangohia te 8 i te -9, ka -17.

$$x^{2}-17=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -17 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-17\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-17\right)}}{2}$$

Whakareatia -4 ki te -17.

$$x=\frac{0±\sqrt{68}}{2}$$

Tuhia te pūtakerua o te 68.

$$x=\frac{0±2\sqrt{17}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{17}}{2} ina he tāpiri te ±.

$$x=\sqrt{17}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{17}}{2} ina he tango te ±.

$$x=-\sqrt{17}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{17} x=-\sqrt{17}$$