Whakaoti i te (x-3)^2=9

$$( x - 3 ) ^ { 2 } = 9$$

Whakaoti mō x

$$x=6$$

$$x=0$$

Ngā Upane Whakamahi Tauwehe

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-3\right)^{2}.

$$x^{2}-6x+9=9$$

Tangohia te 9 mai i ngā taha e rua.

$$x^{2}-6x+9-9=0$$

Tangohia te 9 i te 9, ka 0.

$$x^{2}-6x=0$$

Tauwehea te x.

$$x\left(x-6\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te x-6=0.

$$x=0 x=6$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-3\right)^{2}.

$$x^{2}-6x+9=9$$

Tangohia te 9 mai i ngā taha e rua.

$$x^{2}-6x+9-9=0$$

Tangohia te 9 i te 9, ka 0.

$$x^{2}-6x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -6 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}}}{2}$$

Tuhia te pūtakerua o te \left(-6\right)^{2}.

$$x=\frac{-\left(-6\right)±6}{2}$$

Ko te tauaro o -6 ko 6.

$$x=\frac{6±6}{2}$$

Nā, me whakaoti te whārite x=\frac{6±6}{2} ina he tāpiri te ±. Tāpiri 6 ki te 6.

$$x=\frac{12}{2}$$

Whakawehe 12 ki te 2.

$$x=6$$

Nā, me whakaoti te whārite x=\frac{6±6}{2} ina he tango te ±. Tango 6 mai i 6.

$$x=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$x=0$$

Kua oti te whārite te whakatau.

$$x=6 x=0$$

Ngā Upane mō te Whakaoti i te Pūrua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-3\right)^{2}}=\sqrt{9}$$

Whakarūnātia.

$$x-3=3 x-3=-3$$

Me tāpiri 3 ki ngā taha e rua o te whārite.

$$x=6 x=0$$