Whakaoti i te (x-2)(x+4)-(2x+1)(1-x)

$$( x - 2 ) ( x + 4 ) - ( 2 x + 1 ) ( 1 - x )$$

Aromātai

$$3x^{2}+x-9$$

Ngā Upane Otinga

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x-2 ki ia tau o x+4.

$$x^{2}+4x-2x-8-\left(2x+1\right)\left(1-x\right)$$

Pahekotia te 4x me -2x, ka 2x.

$$x^{2}+2x-8-\left(2x+1\right)\left(1-x\right)$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 2x+1 ki ia tau o 1-x.

$$x^{2}+2x-8-\left(2x-2x^{2}+1-x\right)$$

Pahekotia te 2x me -x, ka x.

$$x^{2}+2x-8-\left(x-2x^{2}+1\right)$$

Hei kimi i te tauaro o x-2x^{2}+1, kimihia te tauaro o ia taurangi.

$$x^{2}+2x-8-x-\left(-2x^{2}\right)-1$$

Ko te tauaro o -2x^{2} ko 2x^{2}.

$$x^{2}+2x-8-x+2x^{2}-1$$

Pahekotia te 2x me -x, ka x.

$$x^{2}+x-8+2x^{2}-1$$

Pahekotia te x^{2} me 2x^{2}, ka 3x^{2}.

$$3x^{2}+x-8-1$$

Tangohia te 1 i te -8, ka -9.

$$3x^{2}+x-9$$

Whakaroha

$$3x^{2}+x-9$$

Ngā Upane Otinga

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x-2 ki ia tau o x+4.

$$x^{2}+4x-2x-8-\left(2x+1\right)\left(1-x\right)$$

Pahekotia te 4x me -2x, ka 2x.

$$x^{2}+2x-8-\left(2x+1\right)\left(1-x\right)$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 2x+1 ki ia tau o 1-x.

$$x^{2}+2x-8-\left(2x-2x^{2}+1-x\right)$$

Pahekotia te 2x me -x, ka x.

$$x^{2}+2x-8-\left(x-2x^{2}+1\right)$$

Hei kimi i te tauaro o x-2x^{2}+1, kimihia te tauaro o ia taurangi.

$$x^{2}+2x-8-x-\left(-2x^{2}\right)-1$$

Ko te tauaro o -2x^{2} ko 2x^{2}.

$$x^{2}+2x-8-x+2x^{2}-1$$

Pahekotia te 2x me -x, ka x.

$$x^{2}+x-8+2x^{2}-1$$

Pahekotia te x^{2} me 2x^{2}, ka 3x^{2}.

$$3x^{2}+x-8-1$$

Tangohia te 1 i te -8, ka -9.

$$3x^{2}+x-9$$