Whakaoti i te (x-2)(x+3)-[(x+5)(x-7)]=2

$$( x - 2 ) ( x + 3 ) - [ ( x + 5 ) ( x - 7 ) ] = 2$$

Whakaoti mō x

$$x=-9$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te x-2 ki te x+3 ka whakakotahi i ngā kupu rite.

$$x^{2}+x-6-\left(x+5\right)\left(x-7\right)=2$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x+5 ki te x-7 ka whakakotahi i ngā kupu rite.

$$x^{2}+x-6-\left(x^{2}-2x-35\right)=2$$

Hei kimi i te tauaro o x^{2}-2x-35, kimihia te tauaro o ia taurangi.

$$x^{2}+x-6-x^{2}+2x+35=2$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$x-6+2x+35=2$$

Pahekotia te x me 2x, ka 3x.

$$3x-6+35=2$$

Tāpirihia te -6 ki te 35, ka 29.

$$3x+29=2$$

Tangohia te 29 mai i ngā taha e rua.

$$3x=2-29$$

Tangohia te 29 i te 2, ka -27.

$$3x=-27$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{-27}{3}$$

Whakawehea te -27 ki te 3, kia riro ko -9.

$$x=-9$$