Whakaoti i te (x-2)^2-(x-3)(x+3)=2x+4

$$( x - 2 ) ^ { 2 } - ( x - 3 ) ( x + 3 ) = 2 x + 4$$

Whakaoti mō x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-2\right)^{2}.

$$x^{2}-4x+4-\left(x-3\right)\left(x+3\right)=2x+4$$

Whakaarohia te \left(x-3\right)\left(x+3\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 3.

$$x^{2}-4x+4-\left(x^{2}-9\right)=2x+4$$

Hei kimi i te tauaro o x^{2}-9, kimihia te tauaro o ia taurangi.

$$x^{2}-4x+4-x^{2}+9=2x+4$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-4x+4+9=2x+4$$

Tāpirihia te 4 ki te 9, ka 13.

$$-4x+13=2x+4$$

Tangohia te 2x mai i ngā taha e rua.

$$-4x+13-2x=4$$

Pahekotia te -4x me -2x, ka -6x.

$$-6x+13=4$$

Tangohia te 13 mai i ngā taha e rua.

$$-6x=4-13$$

Tangohia te 13 i te 4, ka -9.

$$-6x=-9$$

Whakawehea ngā taha e rua ki te -6.

$$x=\frac{-9}{-6}$$

Whakahekea te hautanga \frac{-9}{-6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -3.

$$x=\frac{3}{2}$$