Whakaoti i te (x-2)^2-(2x-1)(2x+1)

$$( x - 2 ) ^ { 2 } - ( 2 x - 1 ) ( 2 x + 1 )$$

Aromātai

$$5-4x-3x^{2}$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-2\right)^{2}.

$$x^{2}-4x+4-\left(2x-1\right)\left(2x+1\right)$$

Whakaarohia te \left(2x-1\right)\left(2x+1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 1.

$$x^{2}-4x+4-\left(\left(2x\right)^{2}-1\right)$$

Whakarohaina te \left(2x\right)^{2}.

$$x^{2}-4x+4-\left(2^{2}x^{2}-1\right)$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$x^{2}-4x+4-\left(4x^{2}-1\right)$$

Hei kimi i te tauaro o 4x^{2}-1, kimihia te tauaro o ia taurangi.

$$x^{2}-4x+4-4x^{2}+1$$

Pahekotia te x^{2} me -4x^{2}, ka -3x^{2}.

$$-3x^{2}-4x+4+1$$

Tāpirihia te 4 ki te 1, ka 5.

$$-3x^{2}-4x+5$$

Whakaroha

$$5-4x-3x^{2}$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-2\right)^{2}.

$$x^{2}-4x+4-\left(2x-1\right)\left(2x+1\right)$$

Whakaarohia te \left(2x-1\right)\left(2x+1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 1.

$$x^{2}-4x+4-\left(\left(2x\right)^{2}-1\right)$$

Whakarohaina te \left(2x\right)^{2}.

$$x^{2}-4x+4-\left(2^{2}x^{2}-1\right)$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$x^{2}-4x+4-\left(4x^{2}-1\right)$$

Hei kimi i te tauaro o 4x^{2}-1, kimihia te tauaro o ia taurangi.

$$x^{2}-4x+4-4x^{2}+1$$

Pahekotia te x^{2} me -4x^{2}, ka -3x^{2}.

$$-3x^{2}-4x+4+1$$

Tāpirihia te 4 ki te 1, ka 5.

$$-3x^{2}-4x+5$$