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Whakaoti mō x
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\left(x-2\right)^{2}=0
Kia whakaotia te koreōrite, me tauwehe te taha mauī. Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 1\times 4}}{2}
Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 1 mō te a, te -4 mō te b, me te 4 mō te c i te ture pūrua.
x=\frac{4±0}{2}
Mahia ngā tātaitai.
x=2
He ōrite ngā whakatau.
\left(x-2\right)^{2}>0
Tuhia anō te koreōrite mā te whakamahi i ngā otinga i whiwhi.
x\neq 2
E mau ana te koreōrite mō x\neq 2.