Whakaoti i te (x-2)^2=(x+6)^2

$$( x - 2 ) ^ { 2 } = ( x + 6 ) ^ { 2 }$$

Whakaoti mō x

$$x=-2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(x-2\right)^{2}.

$$x^{2}-4x+4=\left(x+6\right)^{2}$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+6\right)^{2}.

$$x^{2}-4x+4=x^{2}+12x+36$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}-4x+4-x^{2}=12x+36$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-4x+4=12x+36$$

Tangohia te 12x mai i ngā taha e rua.

$$-4x+4-12x=36$$

Pahekotia te -4x me -12x, ka -16x.

$$-16x+4=36$$

Tangohia te 4 mai i ngā taha e rua.

$$-16x=36-4$$

Tangohia te 4 i te 36, ka 32.

$$-16x=32$$

Whakawehea ngā taha e rua ki te -16.

$$x=\frac{32}{-16}$$

Whakawehea te 32 ki te -16, kia riro ko -2.

$$x=-2$$