Whakaoti i te (x-1)(x-2)-(x+3)(x-4)=

$$( x - 1 ) ( x - 2 ) - ( x + 3 ) ( x - 4 ) =$$

Aromātai

$$14-2x$$

Ngā Upane Otinga

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x-1 ki ia tau o x-2.

$$x^{2}-2x-x+2-\left(x+3\right)\left(x-4\right)$$

Pahekotia te -2x me -x, ka -3x.

$$x^{2}-3x+2-\left(x+3\right)\left(x-4\right)$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x+3 ki ia tau o x-4.

$$x^{2}-3x+2-\left(x^{2}-4x+3x-12\right)$$

Pahekotia te -4x me 3x, ka -x.

$$x^{2}-3x+2-\left(x^{2}-x-12\right)$$

Hei kimi i te tauaro o x^{2}-x-12, kimihia te tauaro o ia taurangi.

$$x^{2}-3x+2-x^{2}-\left(-x\right)-\left(-12\right)$$

Ko te tauaro o -x ko x.

$$x^{2}-3x+2-x^{2}+x-\left(-12\right)$$

Ko te tauaro o -12 ko 12.

$$x^{2}-3x+2-x^{2}+x+12$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-3x+2+x+12$$

Pahekotia te -3x me x, ka -2x.

$$-2x+2+12$$

Tāpirihia te 2 ki te 12, ka 14.

$$-2x+14$$

Whakaroha

$$14-2x$$

Ngā Upane Otinga

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x-1 ki ia tau o x-2.

$$x^{2}-2x-x+2-\left(x+3\right)\left(x-4\right)$$

Pahekotia te -2x me -x, ka -3x.

$$x^{2}-3x+2-\left(x+3\right)\left(x-4\right)$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x+3 ki ia tau o x-4.

$$x^{2}-3x+2-\left(x^{2}-4x+3x-12\right)$$

Pahekotia te -4x me 3x, ka -x.

$$x^{2}-3x+2-\left(x^{2}-x-12\right)$$

Hei kimi i te tauaro o x^{2}-x-12, kimihia te tauaro o ia taurangi.

$$x^{2}-3x+2-x^{2}-\left(-x\right)-\left(-12\right)$$

Ko te tauaro o -x ko x.

$$x^{2}-3x+2-x^{2}+x-\left(-12\right)$$

Ko te tauaro o -12 ko 12.

$$x^{2}-3x+2-x^{2}+x+12$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$-3x+2+x+12$$

Pahekotia te -3x me x, ka -2x.

$$-2x+2+12$$

Tāpirihia te 2 ki te 12, ka 14.

$$-2x+14$$