Whakaoti i te (x-1)(x+2)=x^2-5x+10

$$( x - 1 ) ( x + 2 ) = x ^ { 2 } - 5 x + 10$$

Whakaoti mō x

$$x=2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te x-1 ki te x+2 ka whakakotahi i ngā kupu rite.

$$x^{2}+x-2=x^{2}-5x+10$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+x-2-x^{2}=-5x+10$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$x-2=-5x+10$$

Me tāpiri te 5x ki ngā taha e rua.

$$x-2+5x=10$$

Pahekotia te x me 5x, ka 6x.

$$6x-2=10$$

Me tāpiri te 2 ki ngā taha e rua.

$$6x=10+2$$

Tāpirihia te 10 ki te 2, ka 12.

$$6x=12$$

Whakawehea ngā taha e rua ki te 6.

$$x=\frac{12}{6}$$

Whakawehea te 12 ki te 6, kia riro ko 2.

$$x=2$$